Question

a force of 4.0 n acts on a body of mass 2.0 kg for 4.9s assuming the body to be initially at rest find ​

Answer 1

Answer:

v=9.8 m/s

plz mark me as the brainliest

also do follow me

Answer 2

Explanation:

u = 0

F = 4N

m = 2kg

t = 4.9seconds

v =????

F = mass × acceleration or mass × (v-u)/t

4N = 2 × ( v-0)/4.9

4 × 4.9 = 2v - 0

19.6 = 2v

19.6/2 = 9.8

Therefore final velocity is 9.8m/sec

PLEASE MARK ME AS BRAINLIST