a force of 4.9N is required to slide a body of mass 5 kg on a rough horizontal surface with a constant speed .what is the value of coefficient of friction
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Explanation:
let coefficient be x ang g=9.8m/s²
then
F=xmg
4.9=x×9.8×5
4.9=49x
x=4.9/49
x=0.1
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