Question

a force of 4 N acts on a body of mass 2 kg for 4 seconds. assuming the body to be initially at rest ,find the velocity when the force stops acting,
the distance covered in 10 seconds after the force starts acting

Answer 1

Answer:

V=8 m/s

distance= 80 m

Explanation:

use

F=ma

and simply

V=d/t

Answer 2

velocity= 8 m/s

distance = 64m

Explanation:

F=4N

a= F%m = 4%2 = 2 m/s2

v= u+at

u=o

v=(2×4)= 8 m/s

s=ut+(at^2)/2

s=(0×4)+(2×4×4/2)

s=16 m

also after force stops acting body travels with velocity 8 m/s

s=8×6=48

total distance = 48 + 16 =64m