A force of 4 N is applied on a body of mass 2 gm moving with an initial velocity 3m/s and covered a distance of 10 m. What will be the final velocity of the body?
Answers
Answered by
0
Answer: 200.02
Explanation:
Initial velocity = 3m/s
A force of 4N is applied on it.
The mass of the body as given is 2 gram, we shall convert it to its SI unit i.e. 0.002 kilograms.
Therefore, mass, m = 0.002 kg.
Using Newton's 2nd law of motion,
Force = Mass × Acceleration
=> 4 = 0.002 × a (where a = acceleration)
=>a = 2000 m/s^2
Using the 3rd equation of one dimensional motion we can say that,
Square of final velocity = square of initial velocity + twice of displacement multiplied by its acceleration
=>v^2 = u^2 + 2as
=>v^2 = 3^2 + 2×2000×10
=>v^2 = 9 + 40000
=>v^2 = 40009
=>v = 200.02 m/s (approx)
Similar questions