Physics, asked by sretamandal, 9 months ago

A force of 4 N is applied on a body of mass 2 gm moving with an initial velocity 3m/s and covered a distance of 10 m. What will be the final velocity of the body?​

Answers

Answered by pulkitsinhaor
0

Answer: 200.02

Explanation:

Initial velocity = 3m/s

A force of 4N is applied on it.

The mass of the body as given is 2 gram, we shall convert it to its SI unit i.e. 0.002 kilograms.

Therefore, mass, m = 0.002 kg.

Using Newton's 2nd law of motion,

Force = Mass × Acceleration

=> 4 = 0.002 × a (where a = acceleration)

=>a = 2000 m/s^2

Using the 3rd equation of one dimensional motion we can say that,

Square of final velocity = square of initial velocity + twice of displacement multiplied by its acceleration

=>v^2 = u^2 + 2as

=>v^2 = 3^2 + 2×2000×10

=>v^2 = 9 + 40000

=>v^2 = 40009

=>v = 200.02 m/s (approx)

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