Question

A force of 40 N acting on a body of mass 10 kg changes its velocity from 5 m/s to 25 m/s. Determine :1)Acceleration 2) Time for which force acts 3)Distance covered

Answer 1

Force = F = 40N
Mass = M = 10kg
initial velocity = u = 5m/s
Final velocity = v = 25m/s

1)
F = Ma
a = F/M
a = 40N/10kg
a = 4N/kg
a = 4m/s²
acceleration = a = 4m/s²

2)
a = v-u/t
at = v-u
t = v-u/a
t = 25-5/4
t = 20/4
t = 5s
time = t = 5second

3)
s = ut +1/2 at²
s = 5(5) + 1/2 4(25)
s = 25 + 50
s = 75m

I think it is displacement not distance.
because u given quantity of velocity it is vector quantity and speed is scalar quantity.

so , displacement = s = 75meter