Question

A force of 40 N acting on abody of mass 10 Kg changes its velocity from 5m/s to 25m/s determime acceleration and time for which force acts anddistance answered

Answer 1

f=m×a
40=10×a
a=40/10=4m/s2
a=v-u/t
4=25-5/t
t=20/4=5sec
s=ut+1/2at2
s=5×5+1/2×4×5×5
s=25+50
s=75m
if this helped u i will be thankful

Answer 2

S=1/2(u+v)t
=>ut+1/2at²
=(5*0.2)+1/2*4*(0.2)²
=1+(2*0.04)
=1+0.08
=1.08m