Question

A force of 40 N acts on a body towards the West.
the work done by the force which makes the
body, moves through lm in the West-South direction
(mid-way) is
​

Answer 1

Answer:

W=Fcostheta× displacement

W=40×cos 45° × 1

$w = 40 \times 1 \div \sqrt{2} \times 1$

$w = 40 \div \sqrt{2}$

$w = 20 \sqrt{2}$