A force of 400 N exerts a pressure of 20 N/cm.sq what is the area on which the force act
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Answer:2×10^-3m^2
Explanation:
From
P=F/A
A=F/P
A=400N/2×10^5N/m^2
A=2×10^-3m^2
A=2×10^-3m^2
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