a force of 4N acts on a body of mass 2kg for 4 second.assuming the body to be initially at rest.find distance covered in 10second after force starts acting
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F=m×a
a=2m/s²
now,u=0
t=10seconds
s=ut+½at²
s=½ 2×100
s=100m
a=2m/s²
now,u=0
t=10seconds
s=ut+½at²
s=½ 2×100
s=100m
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