a force of 4n acts on a body of mass 2kg for 4sec . assuming the body to be initially at rest ,find its volecity when the force stops acting.(2)the distance covered in 10sec after the force start action
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since f = ma
4 =2*v*4
v = 4/8
v = 0.5 m/s
distance covered = 0.5 * 4
= 2 m
4 =2*v*4
v = 4/8
v = 0.5 m/s
distance covered = 0.5 * 4
= 2 m
krishnayadav1234:
answe is wrong.answer is (a)8m/s2 (b) 64m
these questions is in physics.
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