Question

A force of 5 N acts of a body at an angle of 60⁰ from the horizontal and displaces it horizontally by 10 m . Force of friction acting on the body of mass 5 kg in this case is 5 N. Find (i) work done by applied force (ii) work done by friction.

Answer 1

Answer:

F= 10/$\sqrt{3}$

Explanation:

Work done in fruit case =F.S.cosθ

=10×2×cos60

10J

Work done in second case is same as 10J= F* S* cosθ

⇒F×2×cos30=10

⇒ F= 10/$\sqrt{3}$