Question

A force of 5 N acts on a 15 kg body initially at rest. The work done by the force during the first second of

motion of the body is

[a] 5 J [b] 5/6 J [c] 6 J [d] 75J​

Answer 1

f=ma

5= 15 * a

1/3=a

in the first second , it will move 1/3 meters

work = force * displacement

=>W= 5 * 1/3

=>5/3 Joule

=>1.67 Joule