Physics, asked by adashokeshinde, 11 months ago

A force of 5 N acts on a 15 kg body initially at rest. The
work done by the force during the first second of motion
of the body is
(a) 5J
(b) 5/6j
(c) 6j
(d) 75j​

Answers

Answered by manjupdsharma
4

Answer:

the answer is 5/6 j .

since acceleration is 1/3 m/s²

u=0m/s.

s= 1/6m

w=F x displacement

w= 5 x1/6

w= 5/6j.

hope it helps .

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