A force of 5 N acts on a 15 kg body initially at rest. The
work done by the force during the first second of motion
of the body is
(a) 5J
(b) 5/6j
(c) 6j
(d) 75j
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Answer:
the answer is 5/6 j .
since acceleration is 1/3 m/s²
u=0m/s.
s= 1/6m
w=F x displacement
w= 5 x1/6
w= 5/6j.
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