Math, asked by ssaritagowami, 11 months ago

find the cost of painting 18 cylindrical pillars of building at rupee 3. 50 per square metre...,if the diameter and height of each pillar is 42cm and 6m respectively.

Answers

Answered by sunny2005rahul
14

Answer: ₹498.96

Step-by-step explanation:

Diameter (d) = 42cm

Radius (r) = 42/2 = 21 cm = 21/100

= 0.21 m

Height (h) = 6 m

Curved Surface Area of cylinder

= 2πrh = 2×22/7×0.21×6

= 7.92 m2

Area of 18 pillars = 18×7.92

=142.56 m2

Cost of painting = ₹3.50×142.56

=₹498.96

Answered by MsPRENCY
29

Given :

  • Diameter of cylindrical pillar = 42 cm; height = 6 m
  • Cost of painting per square meter = Rs. 3.50

To Find :

  • Cost of painting 18 cylindrical pillars.

\huge\underline\green{\tt Solution:}

→ Radius of each pillar

 =\dfrac{Diameter}{2}

 =\dfrac{42}{2}

 = 21\:cm

∵ 1 m = 100 cm,

= 0.21 m

Area of one pillar = 2πrh

So,

For 18 pillars = 18 × 2πrh

 = 18\times 2\times\dfrac{22}{7}\times 0.21\times 6

 = 142.56\:m^2

→ Cost of painting 18 pillars

= 3.50 × 142.56

= ₹ 498.96

Answer : The cost of painting 18 such cylindrical pillars is ₹ 498.96

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