Question

A force of 5 N acts on a body due to which the body moves 10 m at an angle of 60 degree.

Calculate the work done.( Cos 60 = ½)
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Answer 1

Answer :

• Work done by the body when a force of 5 N displaces it 10 m at an angle of 60° is 25 J.

Explanation :

Given :

• Force acting on the body, F = 5 N.
• Displacement of the body, s = 10 m.
• Angle of displacement, θ = 60°.

To find :

• Work done by the body, W = ?.

Knowledge required :

By definition, Work done by a body on a inclined plane is the product of the force and the displacement of the body at the given angle, i.e,

⠀⠀⠀⠀⠀⠀⠀⠀W = F s cosθ

Where,

• W = Work done by the body.
• s = Displacement
• F = Force applied

Solution :

By using the formula for work done and substituting the values in it, we get :

⠀⠀W = F s cosθ

⠀⠀W = 5 × 10 × cos60°

⠀⠀W = 5 × 10 × ½

⠀⠀W = 5 × 5

⠀⠀W = 25

⠀⠀⠀⠀⠀⠀W = 25 J.

Therefore,

• Work done by the body, W = 25 J

Answer 2

Answer:

Given :-

• A force of 5 N acts on a body due to which the body moves 10 m at an angle of 60° .

To Find :-

• How much work done by a body.

Formula Used :-

$\boxed{\bold{\large{Work\: Done\: =\: F\: ×\: s\: ×\: cos\theta}}}$

Solution :-

Given :

• Force (F) = 5 N
• Displacement (s) = 10 m
• Angle of displacement ( $\theta$ ) = 60°
• Cos60° = ½

According to the question by using the formula we get,

⇒ W = 5 × 10 × cos60°

⇒ W = 50 × $\dfrac{1}{2}$

➠ W = 25 J

$\therefore$ Work done by a body is 25 J .