A pole of height 3 metres is struck by a speeding car and breaks into two pieces such that the first piece ½ is of the second. Find the length of both pieces.
wrong answer=report 20 answers...
Answers
Answer:
Total height of pole =3 metres
Total height of pole =3 metresLet length of 2nd piece =x
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21x
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x=21:11
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x=21:11Taking L.C.M. of 2 and 1
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x=21:11Taking L.C.M. of 2 and 1=(21×2) :(11×2)
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x=21:11Taking L.C.M. of 2 and 1=(21×2) :(11×2)=1:2
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x=21:11Taking L.C.M. of 2 and 1=(21×2) :(11×2)=1:2Sum of terms of ratio =1+2=3
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x=21:11Taking L.C.M. of 2 and 1=(21×2) :(11×2)=1:2Sum of terms of ratio =1+2=3∴ Length of 1st part =31 of 3 m
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x=21:11Taking L.C.M. of 2 and 1=(21×2) :(11×2)=1:2Sum of terms of ratio =1+2=3∴ Length of 1st part =31 of 3 m=(31×3)m=1 m
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x=21:11Taking L.C.M. of 2 and 1=(21×2) :(11×2)=1:2Sum of terms of ratio =1+2=3∴ Length of 1st part =31 of 3 m=(31×3)m=1 mLength of 2nd part =31 of 3 m
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x=21:11Taking L.C.M. of 2 and 1=(21×2) :(11×2)=1:2Sum of terms of ratio =1+2=3∴ Length of 1st part =31 of 3 m=(31×3)m=1 mLength of 2nd part =31 of 3 m=(32×3)m=2 m
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x=21:11Taking L.C.M. of 2 and 1=(21×2) :(11×2)=1:2Sum of terms of ratio =1+2=3∴ Length of 1st part =31 of 3 m=(31×3)m=1 mLength of 2nd part =31 of 3 m=(32×3)m=2 mLength of 1st part =1 m
Total height of pole =3 metresLet length of 2nd piece =xLength of 1st piece =21xRatio of length of two parts =21x:1x=21:11Taking L.C.M. of 2 and 1=(21×2) :(11×2)=1:2Sum of terms of ratio =1+2=3∴ Length of 1st part =31 of 3 m=(31×3)m=1 mLength of 2nd part =31 of 3 m=(32×3)m=2 mLength of 1st part =1 mLength of 2nd part =2 m
Mrs.vaishu