Question

A force of 5 Newton acting on a body and angle 30 degree with horizontal Direction this place is horizontal through a distance of 6 m calculate the work

Answer 1

F=5N,angle=30,S=6m,W=FScosa=5×6×1/2=15j

Answer 2

Given

Force = 5N

Displacement = 6m

Angle between the force and the displacement is 30°

To Find

Work Done?

Solution

☯ Work = Fs cosθ

Here as the value of θ is 30°, then the value of cosθ = cos 30° which is √3/2

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✭ According to the Question :

→ Work = Fs cosθ

F = Force = 5 N

s = Displacement = 6 m

θ = Angle between the force & the Displacement = 30°

→ Work = 5 × 6 × cos 30°

→ Work = 5 × 6 × √3/2

→ Work = 30 × √3/2

→ Work = 15 × √3

→ Work = 15√3 J

or

→ Work = 15 × 1.73

→ Work = 25.95 J

∴ The work done by the force is 25.95 J