A force of 50 kgf is applied to the smaller piston of a
hydraulic machine. Neglecting friction, find the force
exerted on the large piston, if the diameters of the
pistons are 5 cm and 25 cm respectively.
please tell with steps
giving 20 points
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We know that Pressure on both the Piston should be same,
∴Pressure on smaller Piston=Pressure on larger Piston
Area of smallerForce on smaller=Area of largerForce on larger
∴ Force on Larger=Area of smallerForce on smaller×Area of larger
⇒2.5×2.5×3.1450×12.5×12.5×3.14=1250kgf
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