A force of 50 N acts on a body of mass 8 kg at rest for 4 seconds.
a) What was the initial kinetic energy of the body?
b) What was the acceleration produced in the body?
c) What was the velocity of the body after 4 seconds?
d) What was the kinetic energy of the body after 4 seconds?
e) What was the distance moved by the body in 4 seconds?
f) Calculate the work done by the force.
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Answers
Answer:
a) Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.
b) Newton's second law says that when a constant force acts on a massive body, it causes it to accelerate, i.e., to change its velocity, at a constant rate. In the simplest case, a force applied to an object at rest causes it to accelerate in the direction of the force
c) Initial velocity 3 m/s. This velocity component will not be altered by normal acceleration. hence this component velocity after 4 s is 3 m/s.
d) According to the concept of kinetic energy of rolling & translation energy,hence,Total K.E of rolling body = 12I ω 2 + 12m v2 (V = R ω ) = 12 I ω 2
e