Question

a force of 50 N acts tangentially to a circle of diameter 750 mm its moment about a point situated diametrically oppossit in -----Nmmm ​

Answer 1

Answer:

31000 Nmm

34000 Nmm

35000 Nmm

37500 Nmm

Answer 2

Answer:

The moment of force situated about a point diametrically opposite is 37.5Nm.

Explanation:

The moment of force is called torque. It is defined as the product of the distance from the point to the point of application of the force and the component of the force present perpendicular to the line of the distance.

$\tau=F\times d$              (1)

Where,

τ=torque or moment of force (its unit is Nm)

F=force applied

d=distance from the point of application of force

As given in the question,

F=50N

d=750 mm=750×10⁻³m=0.75m                          

By substituting the required values in equation (1) we get;

$\tau=50\times 0.75=37.5Nm$

Hence, the moment of force situated about a point diametrically opposite is 37.5Nm.