Question

A force of 50 N displace a body by a distance 4m at an angle of 60° to its own direction. Find the amount of work done

Answer 1

work done =FScosO

so

50×4×1/2

100j

Cos 60=1/2

Answer 2

$\huge\bold\pink{Hello!!!!!}$

W=FS cosá

W= 50×4×cos60°

W= 50×4×1/2

W= 50×2

W= 100 J

Thanks