a force of 500 dyne is applied against the motion of a body of mass 50 gram moving at 1 m per second when and where will be the body stop
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since a=F/m=500/50=10cm/s^2=.1m/s^2
so when it will stop v=0
v=u+at
0=1-.1*t
t=1/.1=10sec
s=distance=(v^2-u^2)/2a
=0-1^2/(-2*.1)=5m
so when it will stop v=0
v=u+at
0=1-.1*t
t=1/.1=10sec
s=distance=(v^2-u^2)/2a
=0-1^2/(-2*.1)=5m
worldj:
ans is 10sec and 5m not 100 sec and 50 m
let me see if there is any calculation problem.
now i have corrected.you can see.
did you understand the solution.
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