Physics, asked by abhishektagad485, 11 hours ago

A force of 500 N is to be resolved into two forces P and Q parallel to and in the direction of line of action of F and acting

one on each side of F at a distance of 3 and 2 units respectively. The values of P and Q are

Answers

Answered by saurabhjagtap030

0

Answer:

this contain 200N and 300N

then answer is option c

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