Question

INTEGRATE...........

Answer 1

Step-by-step explanation:

∫fg′=fg−∫f′g

f =arccos(x), g′ =x/√1−x^2

f′ =−1/√1−x2, g =−√1−x2

= −√1−x2arccos (x)−∫1 dx

Now solve: ∫1 dx, apply constant rule: =x

Plug in our solved integrals:

−√1−x2arccos(x)−∫1dx =−√1−x2arccos(x)−x

1−x2arccos(x)−∫1dx =−√1−x2arccos(x)−xThus the answer is:

−√1−x2arccos(x)−x+C

Answer 2

Step-by-step explanation:∫fg′=fg−∫f′gf =arccos(x), g′ =x/√1−x^2f′ =−1/√1−x2, g =−√1−x2= −√1−x2arccos (x)−∫1 dxNow solve: ∫1 dx, apply constant rule: =xPlug in our solved integrals:−√1−x2arccos(x)−∫1dx =−√1−x2arccos(x)−x1−x2arccos(x)−∫1dx =−√1−x2arccos(x)−xThus the answer is:−√1−x2arccos(x)−x+C

hope it help u mate ....

√\_______Anushka❤