Question

A force of 5000n is applied over a vehicle of 4000kg then in how much time the speed of the vehicle will increase from 20m/s to 120m/s

Answer 1

Answer:

Force, F = 5000 N

Mass, m = 4000 kg

Let acceleration be a , time be t and

Initial velocity, u = 20 m/s

Final velocity, v = 120 m/s

Explanation:

As , F = m×a

5000 = 4000 × a

=> a = 5000/4000 = 5/4 = 1.25 m/s²

Using first law of motion

v = u + at

=> t = v - u

a

=> t = 120 - 20

1.25

=> t = 100 × 100 = 20 × 4 = 80 seconds

125

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