A force of 50N acts on a body and moves it a distance of 4 m on a horizontal surface . Calculate the work done if the distance of force is at an angle of 60° to the horizontal surface.
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Answer:
100N
Explanation:
horizontal force= fcos60
= 50x1/2= 25
work done = force x displacement
= 25x4= 100joule
since there is no displacement in y direction so work done in y direction is 0.
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