Question

The floor of a building consists of 2000 tiles which are rhombus shaped and each of its diagonals are
40 cm and 25 cm in length. Find the total cost of polishing the floor if the cost per m² is 15.

please help me!​

Answer 1

Answer :-  ₹150000

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Given :-

• Total no. of tiles
• Diagonals of rhombus - 40cm and 25cm
• Cost of polishing per m²

To Find :-

• Cost of polishing 2000 tiles.

Solution :-

Area of rhombus = Area of 1 tile

Area of Rhombus = $\frac{1}{2} *d_{1} *d_{2}$

= 1/2 x 40 x 25

= 20 x 25

= 500cm²

Area of 1 rhombus = 500cm²

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Area of 2000 rhombus = 2000 x 500

= 1000000cm²

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Converting cm² to m² :-

1000000cm² = 100m²

-----------------

Cost of polishing 1m² = ₹15

Cost of polishing 10000m² = 15 x 100

= ₹1500

Answer 2

Answer:

Rs.1,500

Explanation:

Given:

Total number of tiles=2000

As tiles is in the shape of rhombus and diagonals are given 40 cm and 25 cm respectively

d1=40 cm

d2=25 cm

Area of rhombus=Area of one tile

We know that

Area of rhombus=1/2×d1×d2

=1/2×40×25

=500 cm^2

Area of 2000 tiles=2000×500

=1,000,000 cm^2

1,000,000 cm^2 in m^2

$\frac{1000000}{10000}$

$100 {m}^{2}$

Cost of polishing 1 m^2= Rs.15

Cost of polishing 18m^2=15×100

=Rs.1500

_______________

Cost of polishing the floor is 1500