Question

A force of 5N acting on a body at a angle of 30 degree with an horizontal direction displaces it horizontally through a distance of 6m .Calculate the work done .

Answer 1

given,
force = 5 N
angle formed = 30°
displacement = 6 m
therefore work done ,
= F*s*cosθ
= 5 * 6 * cos (30)
= 30 * 0.866...
= 25.98 J
therefore work done = 25.98 J
  i hope that it will help u..............................^_^

Answer 2

Answer:

force = 5N

angle formed = 30⁰

displacement = 6m

therefore , work done

f × s× cos o

5 × 6 × cos (30)

30 × 0.866.......

25.98 joule