a force of 5N acts on 20kg at rest the work done in 3rd second is?
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a=F/m
a=1/4
t=3×60=180sec
u=0
s=ut+1/2×ut^2
s=0+4050
W=FS
W=5×4050
W=20250J
hope it helps!!
a=1/4
t=3×60=180sec
u=0
s=ut+1/2×ut^2
s=0+4050
W=FS
W=5×4050
W=20250J
hope it helps!!
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