Question

a force of 5n acts on a body and displaces it in direction of force 6mtr. what is the work .​

Answer 1

ProvidEd that:

• Force = 5 Newton
• Displacement = 6 metre

To calculAte:

• The work done

SolutioN:

• The work done = 30 J

Using concept:

• Work done formula

Knowledge required:

• SI unit of displacement = m
• SI unit of work = Joule (J)
• SI unit of force = Newton (N)

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{W \: = F \times s}}}}}}$

Where, F denotes force, W denotes work done and s denotes displacement.

RequirEd solution:

→ Work = Force × Displacement

→ W = F × s

→ W = Fs

→ W = 5(6)

→ W = 30 J

→ Work = 30 Joule

Additional KnowlEdge:

➟ Work - If a body get displaced when a force acts on it, work it said to be done. Work is measured by the product of force and displacement of the body along the direction of force. If a body get displaced by s when a force f act's on it, then the work w be ${\small{\underline{\boxed{\sf{Fs \: cos \theta}}}}}$

Where, Ø denotes angle between force and displacement

⋆ If both force and displacement are in the same direction, then W = Fs

Answer 2

★ Required Answer ★

• Work = 30 joule

★ Given ★

• Force = 5 Newton
• Displacement = 6m

★ To find ★

• Work done

★ Formula used ★

• Work = Force × Displacement
• W = F × s

★ Solution:- ★

• ➢ W = F × s
• ➢ W = 5 × 6
• ➢ W = 30 J

hence the work is 30 Joule.