Question

A force of 5N change the velocity of a body from 10 m/s to 20m/s in 5 sec . How much force is required to bring about the same changes in 2sec

Answer 1

initial velocity , u = 10 m/s
final velocity , v = 20 m/s
time taken , t = 5 sec
use formula , v = u + at
20 = 10 + 5a => a = 2m/s²

we know, from Newton's 2nd law of motion,
F = ma
5 = m × 2 => m = 2.5 kg

now we have to find Acceleration when changes the velocity from 10m/s to 20m/s in just 2 sec.
so, a = (20 - 10)/2 = 5 m/s²

now force , F' = ma = 2.5 × 5 = 12.5 N

hence, 12.5 N force is required to bring about the same change in 2sec.

Answer 2

HEY DEAR ... ✌️

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=) Given ,
Initial velocity (u) = 10 m/s

Final velocity (v) = 20 m/s

Time taken (t) = 5 sec

we can easily find acceleration (a) by using

=) v = u + at .

putting the values .

=) 20 = 10 + 5a

=) 5a = 20 - 10

=) a = 2 m/s^2 .

Also , we know , Newton's II nd law of motion ,

=) F = ma

putting the values .

=) 5 = m × 2

=) m = 2.5 kg

Now , we have to find Acceleration velocity from 10m/s to 20m/s in just 2 sec.

So , a = (20 - 10) / 2

= 5 m/s²

Now force , F''= ma

putting the values .

= 2.5 × 5
= 12.5 N (ans.)

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HOPE , IT HELPS ... ✌️