a force of 5N gives a mass m1 an acceleration of 8m/s2 a mass m2 an acceleration of 24m/s2 the acceleration if both the masses are tied together is
Answers
Answered by
807
For the first body,
F=5N
mass=m₁
a=8m/s²
Now, F=ma
So, 5=m₁ * 8
So, m¹=5/8 kg
For second body,
F=5N
mass= m₂
a=24 m/s²
Now, F=ma
So, 5=m₂ * 24
So, m₂=5/24 kg
Combined mass of both bodies, m₁+m₂= 5/8 + 5/24
= (15+5)/24
= 20/24 kg
Now, m= 20/24 kg
F= 5N
a= ?
F=ma
So, 5= 20/24 * a
So, a=5*24/20
So, a= 6m/s²
Thus the acceleration produced will be 6 m/s²
F=5N
mass=m₁
a=8m/s²
Now, F=ma
So, 5=m₁ * 8
So, m¹=5/8 kg
For second body,
F=5N
mass= m₂
a=24 m/s²
Now, F=ma
So, 5=m₂ * 24
So, m₂=5/24 kg
Combined mass of both bodies, m₁+m₂= 5/8 + 5/24
= (15+5)/24
= 20/24 kg
Now, m= 20/24 kg
F= 5N
a= ?
F=ma
So, 5= 20/24 * a
So, a=5*24/20
So, a= 6m/s²
Thus the acceleration produced will be 6 m/s²
Answered by
303
Answer:
Explanation:
Given :-
Force, F = 5.0 N
Acceleration of the first body, a₁ = 8.0 m/s²
Acceleration of the second body, a₂ = 24 m/s²
To Calculate :-
Acceleration for a body of mass, m₁ + m₂ = ??
Formula to be used :-
F = ma
Our first problem is to find m₁ and m₂.
Therefore, using : m₁ = F/a₁ and m₂ = F/a₂
m₁ = 5/8 kg and m₂ = 5/24 kg
Therefore, m = m₁ + m₂
= 5/8 + 5/24
= 15 + 5/24
= 20/24 kg
Hence, a = F/m = 5/20/24
a = 15 + 5/24 = 120/20 = 6.0 m/s².
Hence, the masses are tied together is 6.0 m/s².
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