A force of 5N is acting on an object. The object is displaced through 2m in the direction of the force. If the force acts on the object all through the displacement then work done is 5N multiply 2m =10Nm or 10J.
Answers
Answered by
35
total force= 5N
distance covered= 2m
than , total work done= fscos€
hence, total work done = 5N× 2m cos 0°
= 10Nm or 10 j
( both are right answer).
I hope it may help you.
regards:-
saurya
distance covered= 2m
than , total work done= fscos€
hence, total work done = 5N× 2m cos 0°
= 10Nm or 10 j
( both are right answer).
I hope it may help you.
regards:-
saurya
Answered by
11
Here, in this query the force,(F) and displacement,(s) is given and we have to find the work done,(w) . By applying the formula of Work done we can get value.
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