Question

A force of 6 N acts on a body of mass 1.5 kg for 2 s.the body is at rest .
find :
1. It's velocity when the body stops acting
2.the distance covered in 5s after the force starts acting.

Answer 1

f=ma=m*v-u/t=1.5*v-0/2. 6N=1.5*v/2 12=1.5v 12=3/2v 24/3=v=8m/s distanc=velocity*time=8*5=40meter

Answer 2

Answer:

Explanation: As we know that

1. Force(F) = mass(m)*acceleration(a)

and, a = v-u/t

F=m*v-u/t

Here initial velocity=0

F= m*v/t

6=1.5*v/2

6*2=1.5*v

v=8m/s

2. velocity=8m/s

time=5s

distance=velocity*time=8*5=40m