Question

A force of 60N is applied on the tip of a nail of cross-section 0.001cm the pressure on the tip of nail is

Answer 1

Answer:

Pressure=Force/Area=60/0.00001=6000000 N/m^2

Answer 2

The pressure on the tip of nail is :

• Given : Force applied on tip of nail, F = 60 N, Cross section area of tip, A = 0.001 cm^2 = 10^-3 cm^-2 = 10^-7 m^-2

• We know that pressure is the measure of force per unit area applied on the surface of the object.

• P = Force applied / Area = F / A

= 60 / 10^-5 = 60×10^7 N m^-2