Question

A force of 6N acts on a body at rest and of mass 1kg.During this time,the body attains a velocity of 30 m/s.The time for which the force acts on the body is?

Answer 1

Here is your answer. Hope you will understand this.

Thank you.

Answer 2

given

f=6N

m=1kg

v=30m/s

u=0m/s

a=?

a=(v-u)/2

a=30-0/t

a=30/t

according to question

$f =ma$

6=1×30t

6=30/t

6t=30

t=30/6

t=5s

f=