Question

A force of 6N acts on a body of mass 1.5kg for 2 sec.assuming the body to be initially at rest , find
i.its velocity when the force stops acting
ii.the distance covered in 5sec after force starts acting​

Answer 1

Answer:

i) 4m/s {not sure about this one}

ii) 50s ( using formula v=u +at and s =ut + 1/2 at^2

Explanation:

u=0

F=6N

t=2s

m=1.5 kg

Answer 2

Answer:

8 acceleration and 32 metres is the answer