a force of 72 dyne is inclined to the horizontal at an angle of 60 degree find the acceleration in a mass of 9g which moves in a horizontal direction.
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Answered by
83
since force is inclined at 60° so its horizontal component will be F cos60°..
Fcos60°= m×a
Fcos60°/m=a.... a=4m/sec^2
Fcos60°= m×a
Fcos60°/m=a.... a=4m/sec^2
Answered by
132
Hey mate!!
Mass = 9g
Given force is applied of an inclined plane = 72 dyne.
It's horizontal force will be = Fcos60°
= 72 × ½
= 36 dyne
Force [ F ] = mass × acceleration
36 = 9 × acceleration
Acceleration = 4 cm/s²
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