Question

a force of 80N acting on a certain mass for 3 seconds Gives its a velocity of 6m/s find the mass of a body if the body intial at rest

Answer 1

F=m x a
$a = v - u \div t$
a = 6-0/3
a=6/3
$a = 2ms { - }^{2}$
80 N=m x 2
80/2=m
40 kg = mass

Answer 2

Given,

v=6 m/s

Since body is initially at rest u=0

t=3s

We know ,

a=v-u/t

a=6-0/3

a= 2m/s^2

Given:F=80N

We know F=m*a

m=F/a=80/2=40

m=40Kg