x^4+x^3+x^2+x+1(x+1)
Answers
Answered by
0
This quartic has four zeros, which are the non-Real Complex 5th roots of 1, as we can see from:
(x−1)(x4+x3+x2+x+1)=x5−1
So if we wanted to factor this polynomial as a product of linear factors with Complex coefficients then we could write:
x4+x3+x2+x+1
=(x−(cos(2π5)+isin(2π5)))⋅(x−(cos(4π5)+isin(4π5)))⋅(x−(cos(6π5)+isin(6π5)))⋅(x−(cos(8π5)+isin(8π5)))
(x−1)(x4+x3+x2+x+1)=x5−1
So if we wanted to factor this polynomial as a product of linear factors with Complex coefficients then we could write:
x4+x3+x2+x+1
=(x−(cos(2π5)+isin(2π5)))⋅(x−(cos(4π5)+isin(4π5)))⋅(x−(cos(6π5)+isin(6π5)))⋅(x−(cos(8π5)+isin(8π5)))
Similar questions
CBSE BOARD XII,
7 months ago
Biology,
7 months ago
Math,
7 months ago
English,
1 year ago
Math,
1 year ago