Question

A force of 98N acts on a body of mass 10Kg which is at rest calculate
(a) Velocity at the end of 5sec
(b) Distance travelled by the body in 5 sec ​

Answer 1

Answer:

Let the body starts from rest.

∴u=0

Final velocity = distance / time = 50/5 = 10 m/s

Now, using equation of motion, v = u + at

a=

t

v−u

=

10

10−0

=1ms

−2

Force = F= ma = 10kg×1ms

−2

= 10 N