Question

a force of hundred Newton acts on a surface of area 10 cm square normally what are the thrust and pressure on the surface

Answer 1

Thrust = Force = 100 N

Pressure = Force / Area
= 100 N / (10 cm²)
= 100 N / (0.001 m²)
= 10⁵ Pa
= 1 bar

Pressure on the surface is 1 bar

Answer 2

(i.) Therefore the Thrust is 100 N.

(ii.) Therefore the pressure on the surface is 10 N/cm².

Given:

The applied force F = 100 N

The cross-sectional area on which the force F acts = 10 cm²

To Find:

The thrust and the pressure on the surface.

Solution:

The given question can be solved very easily as shown below.

Given that,

The applied force F = 100 N

The cross-sectional area A = 10 cm²

(i.) Thrust:

Thrust is nothing but the force acting normally.

So Thrust = given force

Therefore the Thrust is 100 N.

(ii.) Pressure on the surface:

Pressure on the surface P = ( Force applied ) / ( cross-sectional area )

⇒ Pressure on the surface P = 100/10 = 10

Therefore the pressure on the surface is 10 N/cm².

(i.) Therefore the Thrust is 100 N.

(ii.) Therefore the pressure on the surface is 10 N/cm².

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