Question

a force on a particle of 100g displaces through a distance of 800 cm in 2 seconds if particle is initially at rest find the magnitude of force

Answer 1

Explanation:

Given -

mass=m= 200g= 0.2kg

distance=s=800cm=8 cm

time= t=2 sec

u=0 m/s

find f =??

By second law of motion

s= ut+ 1/2 at^2

=0+1/2 × a×4= 8

=a=2m/ s^2

by second equation of motion

F= ma

0.2× 2 = 0.4 N

Therefore,

magnitude of force is 0.2N