A force on body depends on time t as F=mt+nt^2.The dimensions of m/n is.
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Answered by
5
Here's ur ans. ⤵ ✌
↪ Dimensions of mt and nt^2 must be equal as they are being added
Dimension of ( mt ) = Dimension of ( nt^2)
m = n × time
m / n = t
Therefore dimension of m / n is second (time)
Hope it helps
Answered by
0
Hey mate here is your answer
According to the rule of dimension analysis,
we know that when 2 equation are added or subtracted in the given equation then that 2 equation will have same dimensional formula
Therefore,
dimension formula of (mt) = dimension formula of (nt^2)
by solving this we get ,
m = nt
m÷n = t = [T]
I hope it will help you
please mark it as brainlist
According to the rule of dimension analysis,
we know that when 2 equation are added or subtracted in the given equation then that 2 equation will have same dimensional formula
Therefore,
dimension formula of (mt) = dimension formula of (nt^2)
by solving this we get ,
m = nt
m÷n = t = [T]
I hope it will help you
please mark it as brainlist
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