A force p is equal to 3 mg acts on a block of mass m at an angle of 30 degree with horizontal the friction force between the block and the ground asuming musical to coefficient of friction between the contacting force is
Answers
Answer:
According to the problem
the mass of the block is m and making angle of 30 ° horizontally
therefore,
According to the figure
the vertical component of the force is psinθ= 3mgsin(30°)
= 1.5 mg
The resultant force will be 1.5mg-mg=0.5 mg vertically upwards
As the force is acting upwards from the ground therefore there is no interaction between the block and the ground
Therefore the frictional force is zero
Answer:
According to the problem
the mass of the block is m and making angle of 30 ° horizontally
therefore,
According to the figure
the vertical component of the force is psinθ= 3mgsin(30°)
= 1.5 mg
