a force produces an acceleration of 16m/s in a body of mass 0.5 kg and an acceleration of 4 m/s in another body .if both the bodies are fastened together,then how much acceleration this force will produce
Answers
Answered by
271
a1= 16 m/s²
m1 = 0.5 kg
force = F = m1a1 = 16 x 0.5 = 8N
same force is applied to the second mass; m2
F = m2a2 = 8N
or
m2 = 8/a2
m2 = 8/4 = 2kg
total mass = m1 + m2 = 0.5 + 2 = 2.5 kg
force is same as before
so,
a = F/M
= 8/ 2.5
= 3.2 m/s²
m1 = 0.5 kg
force = F = m1a1 = 16 x 0.5 = 8N
same force is applied to the second mass; m2
F = m2a2 = 8N
or
m2 = 8/a2
m2 = 8/4 = 2kg
total mass = m1 + m2 = 0.5 + 2 = 2.5 kg
force is same as before
so,
a = F/M
= 8/ 2.5
= 3.2 m/s²
Answered by
49
Answer:
3.2 m / sec²
Explanation:
Given :
Acceleration a = 16 m / sec²
Mass m = 0.5 kg
We know :
F = m a
= > F = 0.5 × 16 N
= > F = 8 N
We have acceleration of another body = 4 m / sec²
= > m' = F / a
= > m' = 8 / 4 kg
= > m' = 2 kg
When both the bodies are fastened M = m + m'
= > M = 0.5 + 2 = 2.5 kg
Now acceleration :
a' = F / M
= > a' = 8 / 2.5 m / sec²
= > a' = 3.2 m / sec²
Hence we get required answer.
Similar questions