Question

Q1. What are the uses of concave mirror? Q2. What are the uses of convex mirror? Q3. What is the mirror formula of the spherical mirror? Q4. What is the magnification of the spherical mirror?

Answer 1

Uses of Concave Mirror:
1) It is used as a shaving mirror
2) It is used in torches, head lights of vehicles.
3) It is used in the solar heating devices as reflectors
4) It is used by dentists as head mirror.

Uses of Convex Mirror:
1) It is used as rear view mirrors in vehicles.
2) It is used as safety mirror in the shop.

The mirror formula for spherical mirror is
1/u + 1/v = 1/F
where u = object distance
v = image distance
and F = focal length of given spherical mirror

Magnification of spherical mirror gives the relative extent to which an image of an object is magnified with respect to the object size
m = Hi/ Ho
where Hi = height of the image
Ho = height of the object
or
m = - v/u.

Answer 2

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Q1. What are the uses of concave mirror?

Q2. What are the uses of convex mirror?

Q3. What is the mirror formula of the spherical mirror?

Q4. What is the magnification of the spherical mirror?

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Ans.1:- Uses Of Concave Mirror

• Used as Shaving mirrors.
• Used as Head mirrors.
• Used as Ophthalmoscope.
• Used as Astronomical telescopes.

Ans.2:- Uses Of Concave Mirror

• Used as rear view mirrors.
• Used in Magnifying glasses
• Used as Street light reflectors .
• Used for Security purposes.

Ans.3:- Mirror formula of the spherical mirror :

• $\large{\frac{1}{f} = \frac{1}{v} + \frac{1}{u}}$

Ans.4:- Magnification of the spherical mirror is the ratio between the image distance to the object distance .

m = $\large\frac{{H}_{i}}{{H}_{o}}$

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1. Concave mirror is a part of the spherical mirror in which the outer side is silvered and the inner side is used as a reflecting surface.
2. Convex mirror is a part of the spherical mirror in which the inner side is silvered and the outer side is used as a reflecting surface.
3. The distance of object 'u', the distance of image 'v', and the focal length of the mirror 'f'.
4. As the object is always above the principal axis, the height of the object is always positive whereas the height of the image may be positive or negative . m = $\large{\frac{-v}{u}}$

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