A force vector applied on a mass is represented as F(an arrow above)= 6i -8j+10k and acc the mass at 1 m/s2. the mass of the body is ??
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Answer:
. A 0.250-kg ball is thrown upwards with an initial velocity of 12.0 m/s at an angle of 30.0 degrees. Determine the acceleration of the ball when it has reached the peak of its trajectory. Assume negligible air resistance. PSYW
Answer: 9.8 m/s/s, down
There is only one force upon the ball - the force of gravity. (Air resistance is negligible; the ball is not on a surface, so there is no friction or normal force; the applied force which projects it into motion does not act upon the ball during its trajectory; there are no springs, strings, wires, or cables attached so there is neither a tension force nor a spring force.) The force of gravity acts downward with a magnitude of m•g = (0.250 kg) •(9.8 m/s/s) = 2.45 N. The net force is 2.45 N; when divided by mass, the acceleration can be found.
a = Fnet / m = (2.45 N, down) / (0.250 kg) = 9.8 m/s/s, down