Question

a force vector f=3i+j-4k is applied at a point (3, 4, -2)find its torque about the point (-1, 2, 4)​

Answer 1

Answer:

$\tau = r \times f$

So first find position vector r

that will be

3-(-1) i + 4-2 j + -2 - 4 k

= 4i + 2j - 6 k

So

$\tau = (4i + 2j - 6k) \times (3i + j - 4k) \\ \: \: \: = (4k + 16j) + ( - 6k - 8i) - (18j - 6i) \\ \: \: \: = - 2i - 2j - 2k$

Answer 2

Answer:

Explanation:

By using given coordinates we first,find position vector then cross product of force and pos. vector.