Question

A forms hcp lattice and B arc occupying 1/3rd of tetrahedral voids, then the formula of compound is

Answer 1

no of tetrahedral voids are twice the no of atoms in the crystal lattice=2N
therefore, 2x6=12 tetrahedral voids
atoms in the tetrahedral voids=12/3=4 atoms
therefore the the formula of compund =AB4

Answer 2

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\purple{R}}}}$

• ❤.. The number of tetralhedral voids formed is equal to twice the number of atoms of element B and only 2/3rd of these are occupied by the atoms of element A.
• ❤..Hence the ratio of the number of atoms of A and B is ${2×(1/3):1 or 4}$ and the formula of the compound is ${A4}$.